(x)=-16x^2+400

Solution for (x)=-16x^2+400 equation:

(x)=-16x^2+400

We move all terms to the left:

(x)-(-16x^2+400)=0

We get rid of parentheses

16x^2+x-400=0

a = 16; b = 1; c = -400;
Δ = b2-4ac
Δ = 12-4·16·(-400)
Δ = 25601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{25601}}{2*16}=\frac{-1-\sqrt{25601}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{25601}}{2*16}=\frac{-1+\sqrt{25601}}{32}
$